operator >= method
Implementation
@override
bool operator >=(DynamicNumber<dynamic> other) {
var n2 = other.toDecimal();
var p = higherPrecision(n2);
return withPrecision(p)._n >= n2.withPrecision(p)._n;
}
@override
bool operator >=(DynamicNumber<dynamic> other) {
var n2 = other.toDecimal();
var p = higherPrecision(n2);
return withPrecision(p)._n >= n2.withPrecision(p)._n;
}